Question

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the velocity of electron in excited state of h atom is 1.093 ×10 ^6m/s
.what is the circumference of this orbit.


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Answer 1

The velocity of an electron is given by the following formula :

V(electron) = (2.18 × 10^6 × z) / n

Where :

n = The number of the orbit

z = the atomic number of the element.

We do the substitution as follows :

1.093 × 10^6 = (2.18 × 10^6 × 1)/n

n = (2.18 × 10^6)/(1.093 × 10^6)

n = 1.9945

n = 2

Radius of the orbit = 0.53n^2

r = 0.53 × 4 = 2.12

Circumference = 2pie × r

= 2.12 × 2 × 3.142 = 13.32

The circumference of the orbit is thus given as 13.32.