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Answer 1

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HERE IS YOUR ANSWER:-


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Answer 2

here is your solution too

Given: <ACD=<ABC
<BCP=<PCD

To Prove:<APC=<ACP

Proof: <APC = <ABC + <BCP
<ACP = <PCD+<ACD
it can be written as
<ACP = <BCP+<ABC. ____equation (1)

<APC=<ABC + <BCP. ( exterior < property of triangle) _____equation (2)
subtracting (2) from (1)
<ACP - <APC =(<BCP+<ABC)-(<BCP+<ABC)
<ACP - <APC = 0
<ACP = <APC

PROVED