Physics, asked by aditiss, 10 months ago

Hola Mates ❤
please refer to the attachment and answer the question-
please no spam ❌​

Attachments:

Answers

Answered by Anonymous
7

Answer:

since there is no external force on the system. So total energy will be conserved.

(Total energy) state l =( Total energy) state ll

==> -Gmm'/1 = 0.5 mv^2 +  0.5 mv * 2-Gmm'/0.5

==> -Gmm' = 1/2(mv^2 + m'v'^2) - 2Gmm'

==> 1/2(mv^2 + m'v'^2) = Gmm'

==> (mv^2 + m'v'^2) = 2Gmm'..............................(1)

Here v = velocity of smaller mass(m= 20kg)

v' = velocity of bigger mass( m' = 20kg)

Also momentum of the system will be conserve initial momentum = final momentum

==> O = mv - m'v ( Because both are moving in opposite direction)

==> mv = m'v'

v/v¹=m¹/m

==> v = 2v'......................................(2)

put in v = 2v' in eq. (1)

m(2v')^2 + m'v'^2 = 2G mm'

==>10 * 4v'^2 + 20v'^2 = 2*G (10)*(20)

==> 60v^2 = G 2*200

v²=(20/3)G

(20/3)*6.67*10-¹¹

v`=√6.66*6.67*10-¹¹

2.1*10-5m/s

=4.2*10-5(exponent *5)

so v = 2v'

       

Answered by RJRishabh
2

Here's your answer in the given attachment

hope you'll get it ✌️✌️

Attachments:
Similar questions