hola mates...
plz do in a notebook...
determine which of the following polynomials has (x+1) a factor :
1) x³+x²+x+1
2) x^4+3x³+3x²+x+1
3) x³-x²-(2+underroot 2)x+underroot 2
4) x^4x³+x²+x+1
only meaningful answers plz...
thanks for the help...
#Kratika
Answers
Answered by
9
If ( x + 1 ) will be a factor, reminder will be 0.
By corollary 1 of the remainder theorem, x + 1 = { x - ( -1 ) } ,
1 ) : ( - 1 )³ + ( - 1 )² + ( - 1 ) + 1 = Remainder
- 1 + 1 - 1 + 1 = Remainder
0 = Remainder
remainder is 0, Therefore ( x + 1 ) is the factor of x³ + x² + x + 1
2 ):
( - 1 )⁴ + 3( - 1 )³ + 3( - 1 )² + ( - 1 ) + 1 = Remainder
1 - 3 + 3 - 1 + 1 = Remainder
1 = Remainder
remainder is 1 therefore ( x + 1 ) is not a factor of x^4+3x³+3x²+x+1
3 ):
( - 1 )³ - ( - 1 )² - ( 2 + √2 )( - 1 ) + √2 = Remainder
- 1 - 1 - 2 - √2 + √2 = Remainder
- 4 = Remainder
remainder is - 4 therefore ( x + 1 ) is not a factor of x³-x²-(2+underroot 2)x+underroot 2
4 ):
( - 1 )⁴ + ( - 1 )³ + ( - 1 )² + ( - 1 ) + 1 = Remainder
1 - 1 + 1 - 1 + 1 = Remainder
1 = Remainder
Remainder is 1 therefore ( x + 1 ) is not a factor of x⁴+ x³+x²+x+1
By corollary 1 of the remainder theorem, x + 1 = { x - ( -1 ) } ,
1 ) : ( - 1 )³ + ( - 1 )² + ( - 1 ) + 1 = Remainder
- 1 + 1 - 1 + 1 = Remainder
0 = Remainder
remainder is 0, Therefore ( x + 1 ) is the factor of x³ + x² + x + 1
2 ):
( - 1 )⁴ + 3( - 1 )³ + 3( - 1 )² + ( - 1 ) + 1 = Remainder
1 - 3 + 3 - 1 + 1 = Remainder
1 = Remainder
remainder is 1 therefore ( x + 1 ) is not a factor of x^4+3x³+3x²+x+1
3 ):
( - 1 )³ - ( - 1 )² - ( 2 + √2 )( - 1 ) + √2 = Remainder
- 1 - 1 - 2 - √2 + √2 = Remainder
- 4 = Remainder
remainder is - 4 therefore ( x + 1 ) is not a factor of x³-x²-(2+underroot 2)x+underroot 2
4 ):
( - 1 )⁴ + ( - 1 )³ + ( - 1 )² + ( - 1 ) + 1 = Remainder
1 - 1 + 1 - 1 + 1 = Remainder
1 = Remainder
Remainder is 1 therefore ( x + 1 ) is not a factor of x⁴+ x³+x²+x+1
Anonymous:
thanks bro...
Answered by
2
Hey mate!!!
your answer is attached above !!
Doubts are surely welcome !!!
your answer is attached above !!
Doubts are surely welcome !!!
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