Question

hOla Mates...♥

Solve this......​

Answer 1

Hey mate!

Here's the answer!

$(cosec {}^{2} 65 - tan {}^{2} 25 ) \div (sin {}^{2} 17 + sin {}^{2} 73)1 \div \sqrt{3} tan(90 - 80) \times 1 \div \sqrt{3 \times tan80} \\ = > (cosec {}^{2}(90 - 25) - tan {}^{2} 25) \div (sin {}^{2} (90 - 73) + sin {}^{2} 73)$

Answer 2

$\underline{\underline{\huge\mathfrak{your\:answer}}}$

step-by-step explanation:

For the first one,

It can be easily solved by simplifying and using basic identities of trignometry.

Whole process is in attachment.

kindly refer to it plzz.

Forthe second one,

It can also be easily solved by the help of identity of trignometry.

The whole process and identity used are in the attachment.

Kindly refer to it also.