Question

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Answer 1

Explanation:

The angular frequency of the LCR circuit is:

$w(omega) = \frac{1}{ \sqrt{lc} }$

here:

L=1.5 H ; C=35 micro farad ; R= 20 ohm

putting the value in the above formulae, we get:

$= > \frac{1}{ \sqrt{(1.5) \times (35 \times {10}^{ - 6}) } }$

=> 138 Hz

When an AC voltage of Angular frequency w(omega) =138 Hz is applied to the circuit, then

w(omega) L=

$138 \times 1.5 = 207$

=>So inductive resistance will be= 207 ohm

Also,

$capacitive \: reactance = \frac{1}{w(omega) \times c}$

$\frac{1}{138 \times (35 \times {10}^{ - 6}) } = 207 \: ohm$

$impendence </strong><strong>(</strong><strong>Z</strong><strong>)</strong><strong> </strong><strong> </strong><strong>= \sqrt{ {r}^{2} + {(wl \: - \frac{1}{wc} )}^{2} }$

This the condition of resonance. The rms resonant current in the circuit is:

=> I=V/Z

i.e.

$\frac{200}{20} = 10$

So, resonant current will be: 10 A

Note: here The power is transferred to the resistor only

therefore :

Average power= (I*I) *R

=> (10A * 10A)* 20 ohm = 2000 W

Hence, the average power transferred is 2000 W.

HOPE IT HELPS YOU

Answer 2

Answer:

the power transfered is 2000W