Question

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Question :

Find the area of the sheet required to make a cylindrical container. Which is open at one side and whose diameter is 28 cm and height is 20 cm. Find the approximate area of the sheet required to make a lid of height cm for this container.


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Answer 1

✨✨ heya mate ✨✨

here is the answer ➖➖➖➖➖➖➖➖➖➖➖➖➖⬇

I ) Dimensions of the cylindrical container:

diameter ( d ) = 28 cm

radius ( r ) = d/2 = 28/2 = 14 cm

Height ( H ) = 20 cm

Area of the sheet required to make the

container ( A ) = base area + L.S.A

= πr² + 2πrH

= πr( r + 2H )

= ( 22/7 ) × 14 [ 14 + 2 × 20 ]

= 22 × 2 × 54

= 2376 square centimetres

ii ) Dimensions of the lid :

radius( r ) = 14 cm

height ( h ) = 2 cm

Area of the sheet required to make the

lid = πr( r + 2h )

= ( 22/7 ) × 14 [ 14 + 2 × 2 ]

= 22 × 2 × 18

= 792 cm²

I hope this helps you.

: )

Answer 2

$\textbf{SOLUTION}$

Area of the sheet required to make the container is $\textbf{2376 sq cm}$ and approximate area of sheet required to make a lid is $\textbf{792 sq cm.}$

$\textbf{STEP-BY-STEP EXPLANATION}$

Diameter of the container = 28 cm

its radius (r) = 14 cm

its height (h) = 20 cm

Area of the sheet required to make the container

= curved surface area of the container + Area of the base of the container
$2\pi \: rh \: + \: \pi \: {r}^{2} \\ \\ = \: \pi \: r \: (2h + r) \\ \\ = \: \frac{22}{7} \times \: 14 \: (2 \times 20 + 14) \\ \\ = \: 44 \: \times \: 54 \: = \: 2376 \: sq \: cm$

Let the height of cylindrical lid be h¹

» h¹ = 2 cm

Approximate area of sheet required to make a lid of height
$2cm \: = \: 2\pi \: rh \: + \: \pi \: {r}^{2} \\ \\ = \: 2 \: \times \: \frac{22}{7} \: \times \: 14 \: \times \: 2 \: + \: \frac{22}{7} \: \times \: 14 \: \times \: 14 \\ \\ = \: 176 \: + \: 616 \\ \\ = \: 792 \: sq \: cm$

ANSWER : Area of the sheet required to make the container is $\textbf{2376 sq cm}$ and approximate area of sheet required to make a lid is $\textbf{792 sq cm.}$