Question

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Question:-
The area of the symmetrical figure given in the attachment is:

Options:-
(a) 108 cm²
(b) 180 cm²
(c) 81 cm²
(d) 118 cm²

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Answer 1

Answer:

The answer will be 108cm2

Answer 2

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$\LARGE{\underline{\underline{\tt{QUESTION:-}}}}$

The area of the symmetrical figure (refer attachment) is:

(a) $\sf{108\:{cm}^{2}}$

(b) $\sf{180\:{cm}^{2}}$

(c) $\sf{81\:{cm}^{2}}$

(d) $\sf{118\:{cm}^{2}}$

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$\huge{\underline{\underline{\tt{ANSWER:-}}}}$

Given:

A symmetrical figure made of:

• Two rectangles of measures 12 cm and 2 cm.
• Two rectangles of measures 14 cm and 2 cm.
• A square of side 2 cm.

To find:

• The area of the symmetrical figure.

Solution:

$\large\underline{\boxed{\sf{\red{Area\:of\:symmetrical\:figure\:=\:(A + B + C + D + E)\:sq.units}}}}$

Where,

• Rectangle 1 $\rightarrow$ A
• Rectangle 2 $\rightarrow$ B
• Rectangle 3 $\rightarrow$ C
• Rectangle 4 $\rightarrow$ D
• Square $\rightarrow$ E

We know that,

$\sf\rightarrow{Area\:of\:a\:rectangle=\:Length\times Breadth\:sq.units}$

$\sf\rightarrow{Area\:of\:a\:square=\:({Side})^{2}\:sq.units}$

So,

$\sf\underline{\purple{Area\:of\:Rectangle\:(A):-}}$

$\sf\implies{12\times2\:=24\:{cm}^{2}}$

$\sf\underline{\purple{Area\:of\:Rectangle\:(B):-}}$

$\sf\implies{12\times2\:=24\:{cm}^{2}}$

$\sf\underline{\purple{Area\:of\:Rectangle\:(C):-}}$

$\sf\implies{14\times2\:=28\:{cm}^{2}}$

$\sf\underline{\purple{Area\:of\:Rectangle\:(D):-}}$

$\sf\implies{14\times2\:=28\:{cm}^{2}}$

$\sf\underline{\purple{Area\:of\:Square\:(E):-}}$

$\sf\implies{{2}^{2}\:=4\:{cm}^{2}}$

Total area of the figure:

$\implies 24 + 24 + 28 + 28 + 4$

$\implies 48 + 56 + 4$

$\implies 108$

‎

Final answer:

• Area of the given symmetrical figure is $\large\underline{\boxed{\mathrm{\green{108\:{cm}^{2}.}}}}$
• Therefore, Option: a is the answer.

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$\large{\bold{Note:-}}$

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