Question

hola......

▶️Sania has a piece of land which is in the shape of rhombus she won her one daughter and 17 to work on the land and produce different crops Edward the land into two equal part if the perimeter of the land 400 metre and one of the diagonal is 160 metre how much area each of them will get for their crop?




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Answer 1

Answer:

Hello ❣️

here is ur ans ☺️

let ABCD be the field

Perimeter=400 m

So , each side = 400m÷4=100m

i.e AB=AD=100m

Let diagonal BD= 160 m

then semi perimeter of ∆ ABC De is given by

s=

$100 + 100 + 160 \div 2 = 180m$

therefore area of triangle A B C D

$\sqrt{180(180 - 100)(180 - 100)(180 - 160}$

=

$\sqrt{180 \times 80 \times 80 \times 20 {m}^{2} }$

$= \sqrt{4800 {m}^{2} }$

I hope this helps you ☺️

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Answer 2

Answer:

heya..

refer to attachment