Question

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Solve these questions plzzz!❤​

Answer 1

Answer:

(b) Using componendo -dividendo property :

Value of x = 30
Or
Second method :
Let a = √5x ,
b = √(2x-6)
Now,

(a+b)/(a-b) = 4
=> a+b = 4(a-b)
=> a+b = 4a - 4b
=> 5b = 3a
=> 5(√2x-6) = 3(√5x)
on Squaring both sides ,
we get,

25(2x-6) = 9(5x)
divide both sides by 5, we
get
=> 5(2x-6) = 9x
=> 10x - 30 = 9x
=> 10x - 9x = 30
=> x = 30

••••

Answer 2

Let a = √5x,

b = √(2x-6) Now,

(a+b)/(a-b) = 4

=> a+b = 4(a-b)

=> a+b = 4a - 4b

=> 5b = 3a

=> 5(√2x-6)= 3(√5x)

on Squaring both sides, we get,

25(2x-6)= 9(5x)

divide both sides by 5, we

get

=> 5(2x-6) = 9x

=> 10x - 30 9x

=> 10x - 9x = 30

=> x = 30