Question

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★ Need Explanation★​

Answer 1

Hi,

Thank you for posting your question on embibe. Hope your prep is going well.

Here is the answer to your question:

Thermal capacity of ball = mc = 10 cal/oC

Let T be the furnace temperature.

Water equivalent of vessel and contents = mc = 200 gm

Resultant temperature = 40 oC

According to principle of calorimetry, Heat lost by hot body = heat gained by cold body

10 (T-40) = 200 x 30

=> T = 640 oC

Hope this helps you.....