Question

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⭐Find the compond intrest on ₹12600 for 2 years at 10% per annum componded annually ⭐

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Answer 1

Hey mate !!!



Find compound interest of rupees 12600 for 2 years at 10% per annum compounded annually



Answer


Given:-

P=₹12600

T=2

R=10%

Therefore A=?

A=P{1+R/100}^t

=12600{1+10/100}^2

=12600{100/100+10/100}^2

=12600{110/100}^2

=12600{11/10}{11/10}

=126×11×11

=₹15246

Therefore, Amount=₹15246

Therefore,C.I=Amount-Principle

=15246-12600

=₹2646

So,C.I=₹2646(Ans)


Hope this helps!!!

Answer 2

Given principal = 126000, Time n = 2 years, R = 10%.

We know that A = P(1 + r/100)^n

⇒ A = 12600(1 + 10/100)^2

       = 12600(1 + 1/10)^2

       = 12600(11/10)^2

       = 12600(121/100)

      = 126 * 121

      = 15246.

We know that CI = A - P

⇒ 15246 - 12600

⇒ 2646.

Therefore, Compound interest = 2646.

Hope this helps!