Math, asked by blessy96, 1 year ago

holaa

here is ur question mate...

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Answered by sagarmankoti

$Let \: the \: zeroes \: be \: \alpha \: and \: \beta . \\ \sqrt{2} {x}^{2} + 3x - \sqrt{2} \\ \\ \alpha \beta = \frac{c}{a} \\ \: \: \: \: \: \: = \frac{ - \sqrt{2} }{ \sqrt{2} } = - 1$

So, the product of the zeroes is -1.

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Answered by Anonymous

Answer:

-1 is your answer..........

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holaahere is ur question mate...​

Answers

So, the product of the zeroes is -1.

holaa

here is ur question mate...