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14 .
[ i ] x-3 = 0 => x= 3
f(x) = k²x³ - x² + 3x - 1
f(3) = k²*3³ - 3² + 3*3 - 1 = 0
27k² - 9 + 9 - 1 = 0
27k² - 1 = 0
k = √1/27
k = 1/3√3 Answer
[ ii ] x+2 = 0 => x= -2
f(x) = x³ + 6x² + 4x + k
f(-2) = (-2)³ + 6*(-2)² + 4*(-2) + k = 0
-8 + 24 - 8 + k = 0
k = -24 + 16
k = -8 Answer
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