Question

Holla Mates!!!

A man aged 27 marries a woman aged 24, he dies at the age of 81 and she dies at the age of 91. For what
fraction of his life is the man married? For what fraction of her life is the woman a widow?

Please Answer Fast. I will mark the best and understandable answer as brainliest. ​

Answer 1

Answer :-

→ 2/3 and 1/7 respectively .

Step-by-step explanation :-

We have,

→ Man married at an age of 27 .

And, died at an age of 81 .

Thus, the time spent after marriage by man = ( 81 - 27 ) = 54 years .

Therefore, the fraction for man's life = $\sf \frac{54}{81} = \frac{2}{3} .$

And,

→ Woman married at an age of 24 .

So, women is ( 27 - 24 = 3 ) 3 years younger than man .

Thus, woman's age at the time of man's death = ( 81 - 3 ) = 78 years .

Thus, at an age of 78 woman widowed .

And, died at an age of 91 .

Thus, women remain widowed for ( 91 - 78 ) = 13 years .

Therefore, the fraction for woman's life or widow women = $\sf \frac{13}{91} = \frac{1}{7} .$

Hence, it is solved .

Answer 2

Answer:

Step-by-step explanation:

The Total Years of marriage are

              81 - 27 = 54

Total Fraction of Marriage for the man is;

              X = 54/81

Total Fraction of marriage for woman is;

              Y = 91/54

If the marriage stayed for 54 years then;

       The Age of woman when husband Died = 24 + 54 = 78

       The woman remained widow for years = 91 - 78 = 13

Total Fraction of that woman is Widow;

               Z = 91/13 = 1/7