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With What Speed In Miles/Hr ( M/S = 2.23 Miles/ Hr ) Must an Object Be Throw to reach a Height of 91.5 m ( Equivalent to one Football Field ) ? Assume Negligible Air Resistance
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Answers
Answered by
9
Answer:
Final velocity(v)² - Initial Velocity(u)² = 2 * acceleration due to gravity(g) * height(h)
While the object will attain its maximum height the final velocity will be 0 m/s
0² - u² = 2 * -9.8 * 91.5
-u² = -1793.4
u² = 1793.4
u = √1793.4
u = 42.35(appx)m/s
=42.35 * 2.23 mi/s
=94.44
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Answered by
0
Answer
94.43727473831506
Explanation:
0² - u² = 2 * -9.8 * 91.5
-u² = -1793.4
u² = 1793.4
u = √1793.4
u = 42.35 m/s
=42.34855369431169* 2.23 mi/s
=94.43727473831506
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