Physics, asked by Gur555555, 1 year ago

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With What Speed In Miles/Hr ( M/S = 2.23 Miles/ Hr ) Must an Object Be Throw to reach a Height of 91.5 m ( Equivalent to one Football Field ) ? Assume Negligible Air Resistance

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Answers

Answered by Vulkit
9

Answer:

Final velocity(v)² - Initial Velocity(u)² = 2 * acceleration due to gravity(g) * height(h)

While the object will attain its maximum height the final velocity will be 0 m/s

0² - u² = 2 * -9.8 * 91.5

-u² = -1793.4

u² = 1793.4

u = √1793.4

u = 42.35(appx)m/s

=42.35 * 2.23 mi/s

=94.44

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Answered by ghagjashanpreet
0

Answer

94.43727473831506

Explanation:

0² - u² = 2 * -9.8 * 91.5

-u² = -1793.4

u² = 1793.4

u = √1793.4

u = 42.35 m/s

=42.34855369431169* 2.23 mi/s

=94.43727473831506

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