Question

Holla

The base of an isosceles triangle measures 24 cm and it's area is 192 sq.cm . Find it's perimeter.

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Answer 1

HOLA USER ✌

Here's your answer friend,

==> Given : The base of an Isosceles = 24 cm.

And Area Of = 192 sq. cm.

As We know,

A = hb/2

==> 192 = (24h)/2

==> 192 = 12 h

==> h = 16 cm

Using Pythagoras Theorem,

We have,

a^2 = (b/2)^2+h^2

==> a^2 = (24/2)^2 + 16^2

==> a = 20 cm.

Perimeter = 2a + b = 2(20) + 24

==> 64 cm.

Is the required answer.

Hope it helps you.

Answer 2

Answer:

64 cm

Step-by-step explanation:

Given that ;

Area of isosceles triangle = 192 cm²

BC = 24 cm

BM = CM = 12 cm

We know that;

Area of ∆ = $\frac{1}{2}$ * Base * Height

⇒ 192 = $\frac{1}{2}$ * 24 * h

⇒ 192 = 12 * h

⇒ h = $\frac{192}{12}$

⇒ h = 16 cm

Using Pythagoras theorem :

AB² = BM² + AM²

⇒ AB² = 16² + 12²

⇒ AB² = 256 + 144

⇒ AB² = 400

⇒ AB = √400

⇒ AB = 20 cm

Now, perimeter = AB + BC + CA

                          = 20 + 24 + 20

                          = 64 cm

Hence, the perimeter of triangle is 64 cm.