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Solve the que no.:- 7 and que no:- 11.
From chp wave motion
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Step-by-step explanation:
7.
Given,
bulk modulus of water = 220 kg/mm²
= 220 * 9.8 * 10⁶ N/m².
Density = 1.1 * 10³ kg/m³
We know,
Speed of longitudinal waves in water is,
v = √β/ρ
= √(220 * 9.8 * 10⁶)/1.1 * 10³
= 1.4 * 10³ m/s
Now,
Depth h = vt/2
= (1.4 * 10³ * 2.64)/2
= 1848 m
Therefore,
Depth of the sea = 1848 m.
11.
Given,
Speed of sound in air = 332 m/s
Ratio = 4 : 1
Then,
Molecular weight = ( 4 * 28 + 1 * 32 ) / 5
= 144 / 5
= 28.8
We know that,
V₁/V₂ = √M₂/M₁
=> 332/V₂ = √32/28.8
=> 332/V₂ = √1.11
=> 332/V₂ = 1.0535
=> V₂ = 332/1.0535
=> V₂ = ~315 m/s
Therefore,
Speed of sound in oxygen = 315 m/s.
Hope it helps!
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