Question

hollow cylinder of height 1m is both cross sections are closed with the membrane of negligible mass just floats without sinking in a liquid of density 1.9 into 10 to the power 3 kg per metre cube if the outer diameter and the density of the cylinder are one metre and 10 to the power 4 kg per metre cube respectively then inner diameter will be​

Answer 1

Answer:

0.9m is the answer

Explanation:

see the attachment

Answer 2

Thus the inner diameter of the hollow cylinder will be 0.9 m

Explanation:

Here, height of the cylinder, h = 1 m

Outer diameter, D = 1 m

Density of liquid, dl = 1.9 × 10^3 kg m^3

Density of the cylinder,  dl = 104 kg m^3

Let r1 and r2 be the inner and outer radius of the cylinder.

Weight of the cylinder = Weight of the water displaced by it

πh (r2^2 - r1^2) dc x h = πhr2^2h1 x h

(r2^2 - r1^2) dc = r2^2d1  x h

[0.5^2 - r1^2] 10^4 = 0.5^2 x 1.9 x 10^3

0.25 - r1^2 = 0.25 x 1.9 x 10^3 / 10^4

r1^2 = 0.45 m

d = 2 x r = 0.9 m

Thus the inner diameter of the hollow cylinder will be 0.9 m