hollow cylindrical copper pipe is an even meet along its outer and inner diameter 10 cm and 6 cm find the mass of copper used in making the pipe if mass of funds to pay copper is about 9 gram
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Length or height of pipe=210cm
Outer diameter =10cm ⇒ outer radius =5cm
Inner diameter=6cm ⇒ inner radius=3cm
Volume of copper used= Volume of cylinder
=π(r 22 −r 12 )×h=π(5 2−3 2 )×210cm 3
= 722
×210×(5+3)×(5−3)cm 3
=3360cm 3
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