Question

hollow sphere of mass 1 kg and radius 10 cm is free to rotate about its diameter if a force of 30 newton is applied tangentially to it its angular acceleration is

Answer 1

here R=0.1m now torque =R(perpendicular)xF . =0.1x30=3 Nm now torque=Ixangular acc. . =2/3MR² x angular acc so ang acc. = 3x1.5/MR² . = 4.5/10-² . =450

Answer 2

Here your answer mate

About diameter hollow sphere =2/3mr*2