hollow sphere of mass 1 kg and radius 10 cm is free to rotate about its diameter if a force of 30 newton is applied tangentially to it its angular acceleration is
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261
here R=0.1m
now torque =R(perpendicular)xF
. =0.1x30=3 Nm
now torque=Ixangular acc.
. =2/3MR² x angular acc
so ang acc. = 3x1.5/MR²
. = 4.5/10-²
. =450
keerthi23:
no the answer is 450
i guess now it will be helpful
Mark brainliasokt
plzz
ok
Answered by
30
Here your answer mate
About diameter hollow sphere =2/3mr*2
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