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Find zeros of the following polynomials:
li) 6X²-3-7x
​

Answer 1

Answer:

very difficuut cant find

Step-by-step explanation:

Answer 2

Answer:

The equation is given to be : p(x) = 6x² - 3

To find the zeros of the given equation, Equate the given p(x) = 0

⇒ 6x² - 3 = 0

Dividing each term of the equation by 3

⇒ 2x² - 1 = 0

⇒ 2x² = 1

⇒ x² = 1/2

⇒ x = 1/2 and x = -1/2

⇒ α = 1/2 and β = -1/2

Now, α = 1/2

-b/a = -(-3)/6

⇒ -b/a = 1/2

So, α = -b/a

And, β = -1/2

So, β = b/a

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