Math, asked by hemasri49, 7 months ago

Home work
The present age of a is twice that of B.30
years
from how, age of a will be 3/2
of
times
that of Bo find the present ages
d and B.​

Answers

Answered by ashauthiras
0

Answer:

the age of a be 60 years and age of b be 30 year

Step-by-step explanation:

let the age of a be a years and age of b be b years

ATQ

a=2b ...let this eq 1

30 years from now age of a be (a+30)years and age of b be (b+30)years

ATQ

(a+30)=(b+30)×3/2

2a+60=3b+90

from 1

2 (2b) +60=3b+90

4b -3b = 90-60

b = 30

putting the value of b in 1

a=2b =2×30=60

∴ the age of a be 60 years and age of b be 30 year

Similar questions