Question

Homewo
Tichols
GRAde=8
Submathos
1. One number exceeds another number
byb, if the ratio of these number
find the numbers of
is 3:2
EST​

Answer 1

Step-by-step explanation:

We have a puzzle here. We don't know the numbers. We have to find them.

Let the smaller number 'x', then the bigger number will be 'x+5".

But it is given that sum of these two numbers is 29

⇒ x+x+5=29

⇒ 2x+5=29

∴ 2x=29−5

∴ 2x=24

x=

2

24

(Transposing '2' to RHS)

x=12

Therefore smaller number =x=12 and

Bigger number =x+5=12+5=17

Thus the required numbers are 12 and 17