Question

Homolytic fission of the following alkanes forms free radicals CH₃ – CH₃, CH₃ – CH₂ – CH₃, (CH₃)₂ CH – CH₃, CH₃ – CH₂– CH (CH₃)₂. Increasing order of stability of the radicals is
(a) $(CH_3)_3 \overset{\bullet}{C} \ \textless \ (CH_3)_2 \overset{\bullet}{C} - CH_2CH_3 \ \textless \ CH_3 - \overset{\bullet}{C}H - CH_3 \ \textless \ CH_3 - \overset{\bullet}{C}H_2$
(b) $(CH_3)_2 \overset{\bullet}{C} - CH_2CH_3 \ \textless \ CH_3 - \overset{\bullet}{C}H - CH_3 \ \textless \ CH_3 - \overset{\bullet}{C}H_2 \ \textless \ (CH_3)_3 \overset{\bullet}{C}$
(c) $CH_3 - \overset{\bullet}{C}H_2 \ \textless \ CH_3 - \overset{\bullet}{C}H - CH_3 \ \textless \ (CH_3)_2 \overset{\bullet}{C} - CH_2CH_3 \ \textless \ (CH_3)_3 \overset{\bullet}{C}$
(d) $CH_3 - \overset{\bullet}{C}H_2 \ \textless \ CH_3 - \overset{\bullet}{C}H - CH_3 \ \textless \ (CH_3)_3 \overset{\bullet}{C} \ \textless \ (CH_3)_2 \overset{\bullet}{C} - CH_2CH_3$

Answer 1

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(d) $CH_3 - \overset{\bullet}{C}H_2 \ \textless \ CH_3 - \overset{\bullet}{C}H - CH_3 \ \textless \ (CH_3)_3 \overset{\bullet}{C} \ \textless \ (CH_3)_2 \overset{\bullet}{C} - CH_2CH_3$