Question

hon
bs
Eur
Date
À car starts from rest. If the
velocity of the car becomes
1st 1sms after s sec Cakulate
the acceleration of the can​

Answer 1

The distance travelled by car in 15 s

= Area of AOAC

=(1/2)×15×45 = 337.5 m

Distance travelled by scooter in 15 s

= Area of rectangle OCEF

=15×30 = 450 m

Thus, difference between distance travelled by them = 450 m - 337.5 m = 112.5 m

b. Let after time t from start car will catch, up the scooter. In time t, the distance travelled by them are equal.

Distance travelled by car = (1/2)×15×45 + 45( t - 15)

Distance travelled by scooter = 30t

(1/2)×15×45 + 45(t - 15) = 30t

which gives t = 22.5 s

Distance travelled by car or scooter in 22.5 s = 30 x 22.5

= 675 m

So the car catches the scooter when both are at 675 m from the starting point.