Question

Honda active accelerates uniformly from rest to a speed of 7.10m/s over a distance of 35.4m. Determine the acceleration of the bike.

Answer 1

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Answer 2

${\bold{\underline{Hey\:Mate!}}}$

Here's the Answer ❗

${\boxed{\mathcal{Kinematics}}}$

♦Given that

→ Initial Velocity (u) = 0 [ as it starts from rest ]

→ Final velocity (v) = 7.10 m/s

→ Distance (s) = 35.4 m

${\bold{To\:Find}}$ → Acceleration (a)

Here we shall use the third equation of motion ,

v² - u² = 2a.s

Put the values ,

(7.10)² - (0)² = 2a(35.4 )

50.41 = 70.8a

$a = \frac{50.41}{70.8}$

a = 0.712

•°• ${\underline{\underline{\bold{The\:Acceleration \:of\:the\:vehicle\:is\:0.712 m/s^2}}}}$

${\red{\mathfrak{Hope\:This\:Helps!!}}}$

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