honeys age is three times of his son's age. 10 years he was five time his son's age. find their present age ?
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Answer:
let honeys sons age be x
honeys present age= 3x
honeys age 10 years ago= 3x-10
honeys age 10 years ago is also= 5x-50
honeys sons age 10 years ago= x-10
therefore
3x-10=5x-50
=3x-5x=-50+10
=-8x=-40
=x=-40/-8
=x=5
therefore honeys present age is 5 and his fathers age is 15
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