Honour ship sailing in pacific ocean where temperature is 23.4 degree celsius a balloon is filled with 2 litre air
Answers
V1 = 2L
T2 = 299.1 K
T1 = 296.4 K
Ftom Charle’s Law
V1T2 = V2T1
We get
V2 = 2.018 L
2.018 Litres
Corrected Question:
When a ship is sailing in Pacific Ocean where the temperature is 23.4 Celsius, a balloon is filled with 2 Litre of air. What will be the volume of balloon when the ship reaches at the Indian ocean where the temperature is 26.1 Celsius ?
Given:
Temperature in Celsius of Balloon filled with 2 L air (T1)
= 23.4 Celsius
Temperature in Celsius of a balloon when the ship reaches the Indian ocean (T2)
= 26.1 Celsius
Volume of the Balloon (V1) = 2 Litres
Converting the temperature in Celsius to Kelvin (T1)
= 23.4 + 273
= 296.4 Kelvin
Converting the temperature in Celsius to Kelvin (T2)
= 273 + 26.1
= 299.1 Kelvin
For this type of numerical we use Charle's Law.
The Formula is:
Volume 1 / Temperature 1 = Volume 2 / Temperature 2
In Short Form:
V1/T1= V2/T2
Substituting the values known to us in this formula we get:
=> 2 / 296.4 = V2 / 299
=> 299 x 2 = 296.4 x V2
V2 = 299 x 2 / 296.4
V2 = 2.018 Litres
Therefore,volume of balloon is 2.018 Litres when the ship reaches at Indian Ocean where the temperature is 26.1 Degree Celsius.