Question

hoose the correct answer from the given four options in the following questions:
If one of the zeroes of the quadratic polynomial (k-1) x2 + k x + 1 is -3, then the
value of k is​

Answer 1

final answer

k=4/3

Step-by-step explanation:

here we have the value of x= -3

as it is quadratic polynomial therefore,

(k-1)x^2+Kx+1=0

now put the value of x in the above equation

therefore

(k-1)(-3^2)+k*(-3)+1=0

9(k-1)+(-3k)+1=0

9k-9-3k+1=0

9k-3k-9+1=0

6k-8=0

6k=8

k=8/6

k=4/3

Answer 2

Question :

If one of the zeroes of the quadratic polynomial (k - 1) x² + kx + 1 is -3, then the value of k is

Given :

• p(x) = (k - 1)x² + kx + 1

to find :

• value of k

Solution :

let p(x) = (k - 1)x² + kx + 1

given that one of the zeroes is -3 then

p(-3) = 0

= (k - 1) (-3)² + k(-3) + 1

= 9 (k - 1) - 3k + 1 = 0

= 6k - 8 = 0

= k = 4/3