Question

Horizontal component of earth’s magnetic field at a place is √3 times the vertical component. The value of dip at this place is *

(a) 30°

(b) 45°

(c) 60°

(d) 90°​

Answer 1

Answer:

• The value of dip (δ) is 30°

Explanation:

$\rule{300}{1.5}$

Given, that the Horizontal component of earth's magnetic field is √3 times the vertical component at a given place. Now, lets assume that the Horizontal component be represented by Bₕ and Vertical component be represented by Bᵥ, and the relation between them is Bₕ = √3 Bᵥ. From the formula we know that,

$\longrightarrow\sf \tan \delta=\dfrac{B_{v}}{B_{H}}$

Here,

• δ Denotes Angle of dip.
• Bᵥ Denotes Vertical component of magnetic field.
• Bₕ Denotes Horizontal component of magnetic field.

Solving,

$\longrightarrow\sf \tan \delta=\dfrac{B_{v}}{\sqrt{3}\;B_{v}}\\\\\\\\\longrightarrow\sf \tan\delta=\dfrac{1}{\sqrt{3}}\\\\\\\\\longrightarrow\sf \delta=\tan^{-1}\Bigg[\dfrac{1}{\sqrt{3}}\Bigg]\\\\\\\\\longrightarrow\sf \delta=30^{\circ}\\\\\\\\\longrightarrow\large{\underline{\boxed{\red{\sf \delta=30^{\circ}}}}}$

∴ The value of dip (δ) is 30°.

$\rule{300}{1.5}$

Answer 2

Answer:

answer is 30° hopes it helps you

Explanation:

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