Horizontal component of earth's magnetic field at a place is √3 times the
vertical component. What is the value of inclination at that place?
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Given:
Horizontal component of earth's magnetic field = √3 times the vertical component
To find:
Value of inclination at that place.
Solution:
At any place on the earth the magnetic field of earth has two components, one is the horizontal one and the other is the vertical one.
Let Bh= Horizontal component
Bv = Vertical component
α = Angle of dip
As given: Bh = 1/√3 Bv eq(1)
Therefore, Bv = √3 Bh
We know that tan α = perpendicular/ base
tan α = √3 Bh/Bh
tan α = √3
so, α = 60°
Therefore, the required angle of dip is 60°.
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