Physics, asked by aaakings48261, 5 months ago

Horizontal force of 980n is required to slide a body of mass 500kg over a flat surface. the coefficient of friction is ------?

Answers

Answered by Anonymous

Given:-

Horizontal Force = 980N

Mass of Body = 500kg

Acceleration due to gravity = +9.8m/s²

To Find :-

The Coefficient of friction.

Formulae used:-

F = umg

Where,

u = Coefficient friction
m = Mass
g = Acceleration due to gravity.

Now,

→ F = umg

→ F = u × 500 × 9.8

→ F = u × 4900

→ 980 = u × 4900

→ u = 980/4900

→ u = 0.2

Hence, The Coefficient of friction is 0.2

amitkumar44481: Great :-)

Answered by Anonymous

To Find :-

$\\$

• The Coefficient of friction

$\\$

Solution :-

$\\$

We have,

$\\$

• Horizontal Force = 980N

• Mass of Body = 500kg

• Acceleration due to gravity = +9.8m/s²

$\\$

$\underline{\:\textsf{We know that :}}$

$\\$

$\star\;{\boxed{\sf{\purple{F_{\;(Horizontal \: Force )} = umg}}}}\\ \\$

$\\$

$\sf Where,$

•u = Coefficient friction

•m = Mass

•g = Acceleration due to gravity.

$\\$

Substituting the given values :-

$\\$

$\dashrightarrow \sf F=u × 500 × 9.8\\ \\$

$\dashrightarrow \sf 980=u × 500 × 9.8\\ \\$

$\dashrightarrow {\boxed{\frak{\purple{u = 0.2 }}}}\;\\ \\$

$\\$

Hence

_______

The Coefficient of friction is 0.2

$\\$

_________________________________________________________

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