Question

Horizontal range of a projectile is 1000 m when it is projected at an angle 75o from horizontal, then find out its range when it is projected at an angle 30o from horizontal with same speed.​

Answer 1

l hope it will help u ☺️✌️☺️

Answer 2

Answer:

100√3m

Explanation:

Given:-

R= 1000m

angle= 75

$r = \frac{ {u}^{2} \times \sin(2 \alpha ) }{g} \\ 1000 = \frac{ {u}^{2} \times \sin(2 \times 75) }{10} \\ {u}^{2} = \frac{ {10}^{4} }{ \sin(150) } = \frac{ {10}^{4} }{ \sin(90 + 60) } = \frac{ {10}^{4} }{ \cos(60) } = \frac{ {10}^{4} }{ \frac{1}{2} } = 2 \times {10}^{4} \\ \\ u = 100 \sqrt{2}$

now range from angle 30 degree

$r = \frac{2 \times {10}^{4} \times \sin(2 \times 30) }{10} \\ r = \frac{2 \times {10}^{3} \times </strong><strong>√</strong><strong>3</strong><strong> }{10 \times 2} = 100</strong><strong>√</strong><strong>3</strong><strong>m$