Horizonteel range of projectile is maximum when it is fried at an angle of a) 30° 6) 60° 45 d) 90°
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Horizonteel rang of projectile is 60°
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Answer:
C) 45
Explanation:
Correct option is
C
45o
Let Velocity is V and the angle of projection with horizontal is θ.
∴Range, R=g2V2sinθcosθ=gV2sin2θ
⇒dθdR=gV22cos2θ=0 ⇒2θ=90o ⇒θ=45o
⇒dθ2d2R=−gV24sin2θ, at θ=45o ⇒dθ2d2R=−g4V2<0
Hence, at θ=45o , Range is maximum.
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