Horse stable is in the form of cuboid whose external dimensions of 70 metre 3540 surrounded by a cylinder have vertically through diameter 35 metre and it is open from one rectangular faces and find the cost of painting the exterior of the seven at the rate of 2 rupees per metre square
Answers
Answer:
Step-by-step explanation:
Area of cylindrical top be painted
= 1/2 [T.S.A]
=1/2 [2πR (R + H)]
=1/2[2*22/7*35/2(35/2+70]
= 4812.5 m2
• Area of cuboid to be painted = area of three walls
= lh + 2bh
= 70 × 40 +2 × 40 × 35
= 2800 + 2800
= 5600 sq.m
• Total area to be painted
= 4812.5 + 5600
= 10412.5 sq.m
Cost of painting per sq.m= Rs 2
Cost of painting 10412.5 sq.m = Rs 10412.5 × 2
= Rs 20825
Area to be painted
= Area of three walls + Area of cylindrical part.
= 2bh + lh + 1 /2 [2πRH + 2πR2]
= h [2b + l ] + [πR (R + H)]
= 40 [2 × 35 + 70] + 22/7*35/2[35/2 +70]
= 40 [140] + 55 × 87.5
= 5600 + 4812.5
= 10412.5 sq.m
Cost of painting per sq.m= Rs 2
Cost of painting 10412.5 sq.m = Rs 10412.5 × 2
= Rs 20825
Final cost (same as in previous method)
Hence verified