Question

Hospital is 12 km towards east of Rupin’s house. His school is 5 km towards south of Hospital. What is the shortest distance between Rupin’s house and school?

Answer 1

let AB be the distance between hospital and house
and AC be te distance between hospital and school.
to find :- distance between BC , which is shortest way between house and school

now, in triangle ABC
BC(square)=AC(square)+AB(square)
BC(square)= 12(square)+5(square)
BC(square)=144+25
BC(square)=169
BC=13cm

therefore