hot air ballon going downwards with an acceleration .For the hot air ballon to
go upward with same acceleration
How much mass should be
reduced from the balloon
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2
Answer:
Solution :
Let
F
be the upthrust of air in either case <br> In(i) case,
Mg-F=Ma
…(i) <br> In (ii) case
F-(M-m)g=(M-m)a
…(ii) <br> using (i)
(Mg-Mg)-Mg+Mg=Ma-ma
<br> or
M(g+a)=2Ma
<br>
m=2Ma/g+a
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