Question

hot to solve this equation? = (x +5)²

Answer 1

Answer:

just put identity of ( a+b ) ^2 = a^2 + b^2 +2ab

Answer 2

Answer:

On solving $(x+ 5 )^{2}$  we get , $x^{2} + 10 x + 25$  and on further factorizing we get , $x = -5 , x = -5$ .

Step-by-step explanation:

To solve : $(x+ 5 )^{2}$

Solution :

• According to question we are asked to find the value of $(x+ 5 )^{2}$  .
• Here we can see that , $(x+ 5 )^{2}$  is of the form of identity :$(a + b ) ^{2} = a^{2} + 2ab + b^{2}$ .
• Here , $a = x$ and $b = 5$  
• Applying above identity we get ,

       $(x+ 5 )^{2} = x^{2} + 2 ( x ) ( 5 )+ ( 5 )^{2}$

                    $= x^{2} + 10 x + 25$      

• On factorizing $x^{2} + 10 x + 25$ we get ,

        $=x^{2} +5x + 5x + 25\\\\ = x ( x + 5 ) + 5 ( x + 5 ) \\\\= ( x + 5 )(x + 5 )$        

       $x = -5 , x = -5$

Note :

Question for above solution is :  How to solve  $(x+ 5 )^{2}$  ?