Hot water of mass 7 kg at 98degreeC is cooled for taking bath by mixing 14 kg of
water at 100C. Calculate the final temperature of water. Specific heat capacity
of water is 4200J/kg degree C. Neglect the heat taken by the bucket.
Answers
Answered by
2
Answer:
Specific heat capacity of water=4200 J/kgK
By the principle of mixtures,
m x c (T1-T) = m x c x(T-T2)
2 x 4200(80-T) = 8 x 4200(T-25)
(4200 on both sides get cancelled)
160-2T = 8T-200
360 = 10T
T= 36 degree Celcius
Answered by
1
Answer:
Specific heat capacity of water=4200 J/kgK
By the principle of mixtures,
m x c (T1-T) = m x c x(T-T2)
2 x 4200(80-T) = 8 x 4200(T-25)
(4200 on both sides get cancelled)
160-2T = 8T-200
360 = 10T
T= 36 degree Celcius
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