hota mates....
state and prove the angle sum property of a triangle....
plz explain nicely.... & plz don't do on paper...!!!
thanks for the help... ☺
Answers
Answered by
4
Hey Dear Here Is Your Ansr... !!
~~~Angle sum property of triangle states that, sum of interior angles of a triangle is 180°.
prove
Start with the following triangle with arbitrary values for the angles:
~~~~Angle sum theorem
Since angle a, angle b, and angle c make a straight line,
angle a + angle b + angle c = 180 degrees
~~~~Since alternate interior angles are equal, angle a = angle x and angle b = angle y
~~~Therefore, angle x + angle y + angle c = 180 degrees ...
Hope u get it...
~~~Angle sum property of triangle states that, sum of interior angles of a triangle is 180°.
prove
Start with the following triangle with arbitrary values for the angles:
~~~~Angle sum theorem
Since angle a, angle b, and angle c make a straight line,
angle a + angle b + angle c = 180 degrees
~~~~Since alternate interior angles are equal, angle a = angle x and angle b = angle y
~~~Therefore, angle x + angle y + angle c = 180 degrees ...
Hope u get it...
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Answered by
38
To Prove :- Sum of all angles of triangle is equal to 180° .
Proof - Let ABC be a ∆ , as shown in the figure .
Construct - Draw a line MN parallel to side BC of the given triangle .
Since MN is a straight line , it can be concluded that :
∠MAB + ∠BAC + ∠NAC = 180° ……… (1)
SinceMN||BC and AB, AC are transversals,
Therefore, ∠NAC = ∠ACB (a pair of alternate angle)
Also, ∠MAB = ∠CBA (a pair of alternate angle)
Substituting the value of ∠NAC and∠MAB in equation (1),
∠ACB + ∠BAC + ∠CBA= 180°
Thus, the sum of the interior angles of a triangle is 180°.
Proof - Let ABC be a ∆ , as shown in the figure .
Construct - Draw a line MN parallel to side BC of the given triangle .
Since MN is a straight line , it can be concluded that :
∠MAB + ∠BAC + ∠NAC = 180° ……… (1)
SinceMN||BC and AB, AC are transversals,
Therefore, ∠NAC = ∠ACB (a pair of alternate angle)
Also, ∠MAB = ∠CBA (a pair of alternate angle)
Substituting the value of ∠NAC and∠MAB in equation (1),
∠ACB + ∠BAC + ∠CBA= 180°
Thus, the sum of the interior angles of a triangle is 180°.
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