Question

HOTS
Find the greatest number of four digits which is divisible by 15, 20 and 25.
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Answer 1

Answer:

hey mate here is your answer☺️☺️

The greatest number of four digit is 9999.

The factors of given numbers are

15=3\times 5

20=4\times 5

25=5\times 5

The LCM of 15, 20 and 25 is

L.C.M.=3\times 4\times 5\times 5=300

The L.C.M. of given numbers is 300. It means greatest number of four digits which is divisible by 15 20 and 25 must be divisible by 300.

Divide 9999 by 300.

\frac{9999}{300}=33+\frac{99}{300}

The quotient is 33 and reminder is 99.

9999-99=9900

Therefore the greatest number of four digits which is divisible by 15 20 and 25 is 9900.

hope it helps you✌️✌️

Answer 2

ANSWER

FIRST FIND OUT LCM OF 15,20,25

THEN CO SIDER HIGHEST 4 DIGIT NUMBER 9999

THEN DIVIDE LCM TO 9999 AND SUBTRACT REMAINDER FROM 9999

LCM = 300

9999/300

IT LEAVES 99 AS REMAINDER

NOW 9999 - 99 = 9900

SO OUR ANSWER IS 9900

MARK ME AS BRAINLIEST