Hots question. no:3 solve
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Let's solve it by Arithmetic Progression.
This series will form an A.P as first term is 1, second is 3 , third is 5 and so on. By this way the common difference will be 2.
Given,
a = 1
common difference = 2
Number of terms = 13.
Sum of all terms = n/2 [ 2a + ( n - 1 ) d ]
= 13 / 2 [ 2 * 1 + ( 13 - 1 ) 2 ]
=13 / 2 [ 2 + 12 * 2 ]
= 13 / 2 ( 2 + 24 )
= 13 / 2 * 26
= 13 * 13 = 169.
This series will form an A.P as first term is 1, second is 3 , third is 5 and so on. By this way the common difference will be 2.
Given,
a = 1
common difference = 2
Number of terms = 13.
Sum of all terms = n/2 [ 2a + ( n - 1 ) d ]
= 13 / 2 [ 2 * 1 + ( 13 - 1 ) 2 ]
=13 / 2 [ 2 + 12 * 2 ]
= 13 / 2 ( 2 + 24 )
= 13 / 2 * 26
= 13 * 13 = 169.
Anonymous:
Yeah
Let's think about this series 1,2,3,4,5 ....
In this you can find that 5-4 = 4-3 =3 -2 = 2-1
Here we find that a2 - a1 = a3 - a2 = a4 - a3
If any series is in this form then it is in A.P
Bhai ab toh brainliest mark kr do
hmm..
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