Question

HOTS QUESTION:-
Q1. A regular octagon and a square were drawn side-by-side.
The perimeter of the octagon was found numerically equal to
the area of the square.
What is the sum of the perimeters of the two figures, if the
side of the square was '2x'?​

Answer 1

side of square = 2x unit.

perimeter of square = 4× 2x = 8x unit.

area of square = (2x)² = 4x² sq.unit

so perimeter of octagon = 4x² unit.

so , the sum of the perimeters of the two figures

= perimeter of square + perimeter of octagon

= 8x + 4x² unit .

= 4x(x+2) unit.

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