Chemistry, asked by QWERTYSLN2026, 10 months ago

Housewife has 11 litre of solution that contains sodium carbonate solution and benzene solution in the ratio 3:13:1. She adds 250 ml of 3:23:2 solution of sodium carbonate and benzene solution to it and then uses 250 ml of the combined mixture to make strong organic solution how much of pure sodium carbonate solution is she left with?

Answers

Answered by qwtiger
4

Answer:

ln a mixture of 1,000 ml sodium carbonate : benzene solution = 3 : 1.

Hence, sodium carbonate: 750 ml benzene solution 250 ml

A 250 ml of 3 : 2 solution contains 150 ml sodium carbonate solution and l00ml benzene solution.

Total sodium carbonate solution = 900 ml, total benzene solution = 350 ml

After using 250 ml to make strong organic solution , sodium carbonate solution used

= 250/1250 x 900 = 180 ml

pure sodium carbonate solution left = 900 -180 =720ml

Similar questions