how 0.76 m of hg(mercury)= 1.013 ×10^5pa
akansha4959:
can u help me with that question
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Atmospheric pressure P is measured by the formula P = ρgh
Where, ρ = density of mercury = 13.6 × 103 kg/m3 ; g = 9.8 m/sec2
h = height of mercury column = 0.76 m
=> P = (13.6 × 103 kg/m3) (9.8 m/sec2) (0.76 m)
=> P = 1.013 × 10^5 N/m2 = 1.013 × 10^5Pascal (Pa)
[ 1 N/m2 = 1 Pascal]
Where, ρ = density of mercury = 13.6 × 103 kg/m3 ; g = 9.8 m/sec2
h = height of mercury column = 0.76 m
=> P = (13.6 × 103 kg/m3) (9.8 m/sec2) (0.76 m)
=> P = 1.013 × 10^5 N/m2 = 1.013 × 10^5Pascal (Pa)
[ 1 N/m2 = 1 Pascal]
thank you
u mean in which class i study?*
std 9th
icse
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