How 1 amu is equal to 1.6606× 10^-27
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We know that one atomic mass unit is defined as 1/12th the mass of an atom of Carbon-12 isotope.
As such 1 amu=1.6606×10−27 kg
Velocity of light c in vacuum is =2.9979×108 ms−1
Using the Einstein's mass energy equivalence relation we get
E=mc2
E=1.6606×10−27×(2.9979×108)2 J
We also know that 1 eV=1 electronic charge in C×1 V
=1.60218×10−19 J
Therefore, we get
E=1.6606×10−27×(2.9979×108)21.60218×10−19 eV
⇒E=931.5 MeV, rounded to one decimal place
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As such 1 amu=1.6606×10−27 kg
Velocity of light c in vacuum is =2.9979×108 ms−1
Using the Einstein's mass energy equivalence relation we get
E=mc2
E=1.6606×10−27×(2.9979×108)2 J
We also know that 1 eV=1 electronic charge in C×1 V
=1.60218×10−19 J
Therefore, we get
E=1.6606×10−27×(2.9979×108)21.60218×10−19 eV
⇒E=931.5 MeV, rounded to one decimal place
hope my ans is helpful to u
if u like plz a brainlist
MohammedArslan:
I didn't understant that step
We also know that 1 ev=1 ... from there
it is according to E=MC^2
E=1.6606x10^-27 × (3×10^8)^2
E=1.6606×10^-27 × 9×10^16
E= 1.49×10^-10
How it is equal to 931.5
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4
1 amu is the mass of a proton/neutron and since 1.6606 × 10^-27 kg is the weight of proton in kg.
therefore 1amu = 1.6606 × 10^-27 kg.
therefore 1amu = 1.6606 × 10^-27 kg.
In amu the mass of proton is 1.007277
Hoe
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