Question

How 10 grams of magnesium and 5 grams of carbon have same number of atoms

Answer 1

Answer:

I mole of Mg=24g=6.022*10^23 atoms

10g=(10*6.022*10^23)/24

10g=0.25*10^24

12g of carbon = 6.022*10^23 atoms

5g=(6.022*10^23*5)/12

5g=2.5*6.022*10^23

5g=0.25*6.022*10^24

Hence prooved

Answer 2

Atomic weight of   $Mg=24$

One mole of $Mg=24gm=6.023\times 10^{23} mol^{-1}$

$10gm=\frac{6.023\times 10^{23}\times 10 }{24}$

$10gm=\frac{6.023\times 10^{23}\times 5 }{12}$   ⇒⇒  $eq(1)$

The atomic weight of carbon is $= 12$

One mole of $C=12gm=6.023\times 10^{23} mol^{-1}$

$5gm= \frac{6.023\times 10^{23}\times 5 }{12}$     ⇒⇒  $eq(2)$

From equations $1$ and $2$ we can say that $10$ grams of Mg and $5$ grams of C have the same number of atoms.

Learn more about the atomic number and atomic weight

https://brainly.in/question/12895261

https://brainly.in/question/4683348

#SPJ2