Question

How 11/8÷33/32 it becomes 4/3 explain this to me plz​

Answer 1

Answer:

i hope it helps u , thank you

Step-by-step explanation:

It’s quite simple, when ever you see questions like this, try to find if the numbers have linear or exponential relation. If it is non of them, then always try to make a relation between differences. For example, here differences are:

4 - 3 = 1

8 - 4 = 4

17 - 8 = 9

33 - 17 = 16

Now, if you observe differences carefully then you may found that differences are in a chain,

1 = 1^2

4 = 2^2

9 = 3^2

16 = 4^2

So,

4 = 3 + 1^2

8 = 4 + 2^2

17 = 8 + 3^2

33 = 17 + 4^2

Now, if next number is x then,

x = 33 + 5^2 = 58.

Answer 2

Answer:

-4/3.

Let's guess the number is x.

So,

-33/8 ÷ x = 11/2

x= (11/2) × (8/-33)

= -4/3

(33/8)/x = 11/2

33/8 = (11/2) * x

x = (33/8)/(11/2)

Using the J programming language:

J defines rational fractions with an ‘r’. i.e, 33r8, 11r2

J defines division by ‘%’. Type the equation in the J interpreter:

33r8 % 11r2

3r4

So the answer is 3r4 - (3/4).

<<<>>>

Check:

33r8%3r4

11r2

Checked

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