Question

how (3+2√2)-(3+√2) is equal to √2??​

Answer 1

$\bf \huge \fbox \green{answer}$

$(3 + 2 \sqrt{2} ) - (3 + \sqrt{2} ) = \sqrt{2}$

$(3 + 2 \sqrt{2} ) - 3 - \sqrt{2} = \sqrt{2}$

$- 3(3 + 2 \sqrt{2} ) - \sqrt{2} (3 + 2 \sqrt{2} ) = \sqrt{2}$

$- 9 - 6 \sqrt{2} - 3 \sqrt{2} - 2 \sqrt{2} = \sqrt{2}$

$- 9 - 6 \sqrt{2} - 3 \sqrt{2} - 2 \sqrt{2} - \sqrt{2} = 0$

$= - 9 - 12 \sqrt{2}$

Answer 2

QUESTION:-

✯ʜᴏᴡ (3+2√2)-(3+√2) ɪs ᴇϙᴜᴀʟ ᴛᴏ √2??

ANSWER✔

$\sf\implies (3+2 \sqrt{2})-(3+ \sqrt{2})= \sqrt{2}$

$\sf\implies 3+2 \sqrt{2}-3- \sqrt{2}=\sqrt{2}$

$\sf\implies 3-3 +2 \sqrt{2}- \sqrt{2}=\sqrt{2}($

$\sf\implies 2 \sqrt{2}- \sqrt{2}= \sqrt{2}$

$\sf\implies 2 \sqrt{2}- \sqrt{2}= \sqrt{2}$

$\sf\implies 2 \sqrt{2}- \sqrt{2}= \sqrt{2}$

$\sf\implies \sqrt{2}= \sqrt{2}$

$\sf\therefore L.H.S=R.H.S.$

HENCE,PROVED✔

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